F(x)=3x^2+12x+50

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Solution for F(x)=3x^2+12x+50 equation: 



(F)=3F^2+12F+50

We move all terms to the left:

(F)-(3F^2+12F+50)=0

We get rid of parentheses

-3F^2+F-12F-50=0

We add all the numbers together, and all the variables

-3F^2-11F-50=0

a = -3; b = -11; c = -50;
Δ = b2-4ac
Δ = -112-4·(-3)·(-50)
Δ = -479
Delta is less than zero, so there is no solution for the equation

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